x(3x+2)+4=3(x^2+x)

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Solution for x(3x+2)+4=3(x^2+x) equation: 


Simplifying
x(3x + 2) + 4 = 3(x2 + x)

Reorder the terms:
x(2 + 3x) + 4 = 3(x2 + x)
(2 * x + 3x * x) + 4 = 3(x2 + x)
(2x + 3x2) + 4 = 3(x2 + x)

Reorder the terms:
4 + 2x + 3x2 = 3(x2 + x)

Reorder the terms:
4 + 2x + 3x2 = 3(x + x2)
4 + 2x + 3x2 = (x * 3 + x2 * 3)
4 + 2x + 3x2 = (3x + 3x2)

Add '-3x2' to each side of the equation.
4 + 2x + 3x2 + -3x2 = 3x + 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
4 + 2x + 0 = 3x + 3x2 + -3x2
4 + 2x = 3x + 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
4 + 2x = 3x + 0
4 + 2x = 3x

Solving
4 + 2x = 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.
4 + 2x + -3x = 3x + -3x

Combine like terms: 2x + -3x = -1x
4 + -1x = 3x + -3x

Combine like terms: 3x + -3x = 0
4 + -1x = 0

Add '-4' to each side of the equation.
4 + -4 + -1x = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1x = 0 + -4
-1x = 0 + -4

Combine like terms: 0 + -4 = -4
-1x = -4

Divide each side by '-1'.
x = 4

Simplifying
x = 4

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